If you create accounts on various sites with an email address on your new domain keep a list of those. If decide to let the domain expire you need to close the accounts beforehand, otherwise someone else can get access if they purchase the domain.
Also you will likely be playing for the domain forever, so just register/renew it for 10 years, maybe you’ll also get a discount.
deleted by creator
The recorder. It’s easy to get started, there is a lot of good information online (look up Sarah Jeffery), and professional plastic instruments are very cheap. It also requires no special care and doesn’t need maintenance, since it has no moving parts.
The downside is that in order to play larger recorders your hands need to stretch a bit, so I’m no sure if that is a problem if you have joint issues.
The other option is a hand ocarina, but it is very hard to even make a sound, even harder to make it clear and consistent. Also you need to play entirety by ear. It’s a fun challenge, though.
Just buy a new SSD to install Linux on. If you decide to switch back just plug the old one in.
I quite enjoy Nix flakes for this. Only certain languages have good support though (C, Rust, Haskell, OCaml, …).
It’s easier to write that much if you are just making stuff up…
I don’t have 2 mil, how do I get out of this? File for bankruptcy?
Stand a little out of my sun.
Linux is already better than Windows, the latest versions are a mess, and is likely going to get worse.
A package is reproducible if you use the same inputs, run the build, and get the same outputs.
The issue is that the build can produce different outputs given the same inputs. So you need to modify the build or patch the outputs. This is something that is being worked on by most distributions: https://reproducible-builds.org/who/projects/
NixOS is not special in that regard nor are all NixOS packages reproducible.
Nope, nix doesn’t ensure or require that the builds are deterministic. It’s not any better in that regard than other package managers.
It’s not really fully reproducible either.
Remove the wall plug, straighten the paper clip and insert it into the cable in between the wires, reinstall the wall plug.
All is not a “for you” feed, it contains posts from the whole fediverse. You are supposed to add the filter yourself. Find the communities you are interested in, subscribe and then browse that.
deleted by creator
You don’t even need soil, you can just put them on the ground and cover them with hay, and they grow just fine.
Yes, I meant a bouillon or stock cube, sorry for the typo. Or you can use stock or a broth instead of water.
Stock is also pretty easy to make. You can buy a whole chicken and then throw the leftover carcass, skins, bones, with onions, carrots, celery and some herbs into a pot and simmer it for 2 hours.
You can also saute an onion before adding the rice and water, and add a bullion cube, to improve the flavor.
As you already figured out the types are sets with a certain number of elements.
Two types are isomorphic if you can write a function that converts all elements of the first one into the elements of the second one and a function which does the reverse. You can then use this as the equality.
The types with the same number of elements are isomorphic, i.e True | False = Left | Right. For example, you can write a function that converts True to Left, False to Right, and a function that does the reverse.
Therefore you essentially only need types 0, 1, 2, 3, …, where type 0 has 0 elements, type 1 has 1 element, etc. and all others are isomorphic to one of these.
Let’s use (*) for the product and (+) for the sum, and letters for generic types. Then you can essentially manipulate types as natural numbers (the same laws hold, associativity, commutativity, identity elements, distributivity).
For example:
2 = 1 + 1 can be interpreted as Bool = True | False
2 * 1 = 2 can be interpreted as (Bool, Unit) = Bool
2 * x = x + x can be interpreted as (Bool, x) = This of x | That of x
o(x) = x + 1 can be interpreted as Option x = Some of x | None
l(x) = o(x * l(x)) = x * l(x) + 1 can be interpreted as List x = Option (x, List x)
l(x) = x * l(x) + 1 = x * (x * l(x) + 1) + 1 = x * x * l(x) + x + 1 = x * x * (l(x) + 1) + x + 1 = x * x * l(x) + x * x + x + 1 so a list is either empty, has 1 element or 2 elements, … (if you keep substituting)
For the expression problem, read this paper: doi:10.1007/BFb0019443
I would just pick the value from the root of each underlaying balanced binary tree, easy.