• protist
      link
      fedilink
      English
      arrow-up
      3
      arrow-down
      2
      ·
      11 months ago

      I summarized it above, there’s an extra rotation included when the outer circle moves along the inner circle, essentially falling a bit with every roll forward. If the outer circle rolled along a straight line of the same length as the circumference of the inner circle, it would only roll 3 times, but moving around the circle instead adds exactly one extra rotation. That other gent says this is used in calculating orbits too, where you’re also moving forward while constantly falling

      • SpaceNoodle@lemmy.world
        link
        fedilink
        arrow-up
        5
        arrow-down
        4
        ·
        11 months ago

        I read an article about it. Everybody is doing a shit job of describing what happens. The outer circle naturally makes a full rotation as it travels around the inner one, as the path it follows goes around a full 360°, so that counts as one of the rotations it ends up making, which is in addition to the 3 due to travel around the circumference.

        • schmidtster@lemmy.world
          link
          fedilink
          arrow-up
          1
          arrow-down
          3
          ·
          edit-2
          11 months ago

          It’s in the video.

          A circle with a radius of 2 and a circle with a radius of 3 would be 5 rotations.

          • protist
            link
            fedilink
            English
            arrow-up
            7
            arrow-down
            1
            ·
            11 months ago

            First you said add the radii together, then you gave an example subtracting them, but either way this is incorrect. You divide the larger radius by the smaller radius and add 1

          • uphillbothways@kbin.social
            link
            fedilink
            arrow-up
            1
            ·
            edit-2
            11 months ago

            Not quite. With radius 2 and 3 circles, the outer circle would take 2.5 rotations to complete the revolution. You have to set the first circle radius to 1 (divide both radii by the lesser) and then add the radii to calculate the relative circumference of the circle drawn by the motion of the center of the outer circle, so the answer would be calculated like:

            2/2 + 3/2 = 5/2 = 2.5

          • bisby@lemmy.world
            link
            fedilink
            arrow-up
            2
            arrow-down
            1
            ·
            edit-2
            11 months ago

            Its not even remotely what you said. Its A/B+1 or A/B-1 for an interior loop.

            edit: I didn’t need to be this aggressive. It’s VAGUELY what you said. its (A+B)/B. You have missed the /B part… which is A/B + 1.

            in the example you gave, for radius 2 and 3… it would be 3/2 + 1 or 2.5. Not 5 (off by a factor of 2 because /B)

            • schmidtster@lemmy.world
              link
              fedilink
              arrow-up
              1
              arrow-down
              4
              ·
              11 months ago

              They explain multiple ways to do it in the video. A circle with a radius of 2 and a circle with a radius of 3 would be 5.

              • bisby@lemmy.world
                link
                fedilink
                arrow-up
                3
                ·
                11 months ago

                No they don’t

                N is the ratio of the circles and its just +1 or -1 depending on outer or inner.